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The perimeter is 2 a + 2 b, so in this example the perimeter. The area of a rectangle can be calculated by counting the number of small full squares of dimension 1 1 sq. Using the same dimensions, we can calculate the perimeter. The total length of our stadium infield is \(157.4\) meters, but we need to subtract the length of each semicircle from that. Example of calculating the area of a rectangle: Suppose the length is a 6 inches and the width is b 4 inches. Now we just need to find the length of the rectangle. The area of a rectangle can be found by multiplying the length times t.
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That’s one piece of the puzzle completed. Part of the series: Math Formulas & Calculations. Here the width, or the diameter, is \(73\) meters, so our radius is \(36.5\) meters. The diagonal of a rectangle divides it into two congruent right triangles. Since the area of a rectangle is a product of its length and width, we need to find the width. That means that we can find the radius by simply dividing our diameter by \(2\). Find the area of the rectangle below that has a diagonal of 26 and length of 24. Step 4: The area of the rectangle is 100 square units. Step 2: Area of rectangle formula length x breadth. Step 1: Given the length of the rectangle 20 units, breadth of the rectangle 5 units. Step 4: Use the distance formula to calculate the width of the rectangle. Just like with our “tombstone”-shaped problem, problems of this type only give two dimensions of our shape – the total width and the total length.īut that’s all the information that we need! As we saw in the last problem, our width is also the diameter of our circle: We’ll calculate the area of a rectangle with a length of 20 units and a width of 5 units. Side AD side BC the length of the rectangle 2.83. For a real world problem, let’s calculate the area of an outdoor track and field stadium. It’s not hard to see where it gets its name! It’s shaped like a track and field stadium. Notice that we used the “approximately equal to” symbol \(( \approx)\) since our semicircle area is now an approximation.įor our next problem, let’s try to find the area for another related shape, the stadium: